Types of Stirrups: Spacing, Diameter, Cutting Length and Hooks

A stirrup is a closed or open loop of reinforcing bar wrapped around the main bars of a concrete beam. It resists shear and torsion, holds the cage in position while concrete is placed, and stops compression bars from buckling. The same loop in a column is called a tie or hoop.

Most beams use 2-legged closed stirrups of 8 mm bar, spaced 100 mm near the supports and 150 mm at mid-span. Choose more legs when the beam is wide or has more than two bars on a face, a bigger bar when shear is high, and always a 135° hook on closed stirrups. Spacing caps: 0.75d or 300 mm (IS 456), d/2 or 600 mm (ACI 318), 0.75d (Eurocode 2). The drawing and the engineer’s design always override these rules of thumb.
8 mm, 2-leggedThe everyday choice for residential and light commercial beams.
100 / 150 mmClose spacing over 2d at supports, wider spacing in the middle.
135° hookTail of at least 6d and 65–75 mm turned into the core.
L = 2(a+b) + 8dCutting length, out-to-out, for a closed stirrup with two 135° hooks.

What stirrups do inside a beam

Under load a beam bends, and near its supports it also wants to shear. Shear shows up as diagonal cracks at roughly 45° that start low near the support and climb toward the load. Concrete alone resists some of it, then the crack opens and the beam can fail suddenly with no warning. A stirrup crosses the crack and ties the two sides together.

Stirrups have four jobs. They carry shear across diagonal cracks. They resist torsion, but only when they are closed. They hold the top and bottom bars at the right depth while workers walk, vibrate and pour. And they stop compression bars from bowing out. Of these, shear is the one that governs spacing and size.

SupportSupport2d zone · s = 100 mm2d zone · s = 100 mmMid-span · s = 150 mmcrack ≈ 45°Top bars (red) and bottom bars run through all stirrups1st stirrup 50 mm from face+V max at support−V maxV = 0 at mid-span (uniform load)Shear force diagram
Diagram 1. Where the stirrups are tight and why. Shear peaks at the supports, so the first 2d from the face gets 100 mm spacing and the first stirrup sits 50 mm from the face. At mid-span, where shear is near zero, 150 mm is enough.

Types of stirrups

Most articles list shapes (square, rectangular, triangular, diamond) and then leg counts from one to eight. On site, three questions sort everything: is the loop closed, how many legs cross the section, and is the bar straight or spiral?

2-leggedb ≤ ~300 mm4 bars, narrow beam3-leggedtie = 3rd leg6 bars, cross-tie4-leggedwide beam, b 400+8 bars, 2 overlaps6-leggedgirders, heavy shearouter + 2 inner legsU-type (open)no torsion capacityslab ribs, precastCircular/spiralhoop confinementround columns, piles
Diagram 2. Six arrangements you will actually meet. Red dots are longitudinal bars. Teal and orange lines are the extra legs or the second overlapping stirrup.
TypeWhere it is usedNotes
2-legged closedBeams up to about 300 mm wide, 4 main barsThe default. Carries shear and torsion.
3-legged (stirrup + cross-tie)Beams with 3 bars per faceThe middle bar is held by a cross-tie with a 135° hook at one end and a 90° at the other.
4-leggedBeams 400 mm wide or more, heavy shearTwo overlapping closed stirrups. Doubles the steel crossing each crack.
6-legged and aboveTransfer beams, bridge girders, pile capsChosen when shear is too high for 4 legs at a workable spacing.
Open U-stirrupPrecast beams, slab ribs, with a cap barNo torsion resistance. Not for edge beams.
Rectangular or square tieColumnsCalled a tie or hoop. See stirrups vs ties below.
Circular tie or spiralRound columns, pilesConfines the core, improves ductility.

Triangular and diamond stirrups appear in drawings for odd sections such as trapezoidal beams, and for corner bars in non-rectangular columns. They are detail solutions, not standard types, and each bend has to be anchored like any other hook.

Which one to choose

  • Beam width up to about 300 mm, bars on the corners only: 2-legged.
  • Three or more bars across the top or bottom layer: add a cross-tie so no bar sits more than about 150 mm clear from a supported one (ACI 318 sets this limit for columns, and designers copy it for beams).
  • Width 400 mm and above, or shear steel at maximum density at 100 mm: 4-legged before squeezing the spacing below 100 mm. Tight stirrups block the vibrator and make honeycombing likely.
  • Edge beams, balconies, anything with torsion: closed loops only, with 135° hooks.
  • Round column or pile: spiral if the design is for ductility, circular ties if you want easier fabrication.

Stirrup spacing in beams

Three layers of rules set spacing. The code gives a ceiling. The seismic detail gives a floor near the supports. And the concrete’s need to flow gives a practical minimum.

  1. Upper limit. Beyond it a diagonal crack could pass between two stirrups without touching either.
  2. Confinement zone. In seismic design, the length of 2d (IS 13920) or 2h (ACI 318) from the support face has closer hoops. First hoop 50 mm from the face.
  3. Practical minimum. About 75–100 mm. Below this the vibrator cannot enter and aggregate bridges the bars.

Spacing also controls the minimum shear steel. In IS 456 the check is Asv / (b × sv) ≥ 0.4 / (0.87 fy). For a 300 mm wide beam with 2L-8 bars and Fe 500, that gives a maximum spacing of about 365 mm, so the 300 mm cap governs.

Code limits side by side

IS 456 / IS 13920 (India)ACI 318 (US)Eurocode 2 / 8
Max spacing, beam0.75d or 300 mm, smaller of the twod/2 or 600 mm; d/4 or 300 mm when shear steel carries a high share0.75d for vertical stirrups
Minimum shear steelAsv/(b·sv) ≥ 0.4/(0.87 fy)Larger of 0.062√f′c and 0.35, times bw/fytρw ≥ 0.08√fck / fyk
Seismic zone length2d from the face2h from the facehw (medium ductility class)
Seismic spacing≤ d/4, ≤ 8 × smallest bar, ≥ 100 mm≤ d/4, ≤ 6 × smallest bar (typical for 60 ksi), ≤ 150 mm≤ hw/4, 24 dbw, 225 mm, 8 dbL
Hook tail135°, ≥ 6d and ≥ 65 mm135°, ≥ 6d and ≥ 75 mmSet in national annex and detailing rules
Column ties, max spacingLeast of: smallest dimension, 16 × smallest bar, 300 mmLeast of: 16 × bar, 48 × tie, smallest dimensionLeast of: 20 × smallest bar, smallest dimension, 400 mm

Use the table to cross-check a drawing, never as a substitute for the design code that governs your project. Editions change, and national annexes change the numbers again.

Suitable diameter of stirrups

Diameter comes from three limits: shear demand, the main bar size, and what can be bent and handled. Ties in columns have an explicit rule. In IS 456 and Eurocode 2 the tie must be at least one quarter of the largest longitudinal bar and never under 6 mm. ACI 318 sets 10 mm for longitudinal bars up to 32 mm and 13 mm above that.

SituationCommon stirrup sizeReason
Lintels, light beams, spans under 3 m6–8 mmLow shear. 6 mm is fine when the design says so.
Residential and small commercial beams8 mmStiff enough to hold the cage, easy to bend by hand.
Long-span beams, transfer beams, 600 mm+ deep10–12 mmHigher shear, more legs at wider spacing.
Girders, pile caps, deep beams12–16 mmHeavy shear, often with 4 or 6 legs.
Column ties, long bars up to 32 mm8–10 mm¼ of the largest bar, ACI 10 mm.
Column ties, long bars 36 mm+10–12 mmKeeps ties stiff enough to restrain big bars.

When shear demand rises, you have three levers: bigger diameter, more legs, tighter spacing. Raising the diameter is usually the cheapest on site because the number of pieces stays the same.

What spacing and legs do to shear capacity

Steel contribution to shear under IS 456 is Vus = 0.87 fy Asv d / sv. Take a beam with effective depth 450 mm and Fe 500 steel. The chart shows what three common arrangements carry, and how fast capacity drops as spacing opens up. The concrete’s own share, Vc, is added on top and comes from the IS 456 tables.

0100200300400Vus, kN (steel part only)197308394s = 100 mm131205262s = 150 mm98154197s = 200 mm66103131s = 300 mm2L-82L-104L-8d = 450 mm, fy = 500 MPa, Vus = 0.87 fy Asv d / s
Diagram 3. Steel shear capacity for 2L-8, 2L-10 and 4L-8 stirrups at four spacings. At 300 mm, a 2L-8 stirrup carries one-third of what it carries at 100 mm.
Reading it. If the design needs Vus = 150 kN at the support, 2L-8 at 100 mm (197 kN) works, but 2L-8 at 150 mm (131 kN) does not. The fix is 2L-10 at 150 mm (205 kN) or 4L-8 at 150 mm (262 kN). Same beam, three valid answers. Pick the one that keeps the cage easy to concrete.

Hooks and anchorage

A stirrup is only as strong as its anchorage. If a hook opens, the loop stops confining and the shear steel above the crack loses its grip. That is why codes ask for 135° hooks on closed stirrups.

135° hook (use this) tail bends into the core tail ≥ 6d and ≥ 65 mm (IS 13920) · ≥ 75 mm (ACI 318) Stays closed when cover spalls 90° hook (avoid) tail points along cover opens when cover is lost allowed only where code permits Weak anchorage in seismic work Hook position along beam Plan, looking down on top bars Hook corner alternates orange = hook top-front green = hook top-back Keeps the beam top from having a line of weak overlaps Leave hooks in the compression zone
Diagram 4. Left: the 135° hook turns into the core and stays anchored after cover is lost. Middle: the 90° hook can open. Right: alternate the hook corner from one stirrup to the next so the weak overlap does not line up.
  • Bend diameter: inside bend diameter at least 4d for bars up to 16 mm, which is the usual rule on mandrels at bar-bending yards.
  • Tail length: 6d minimum, 65 mm (IS 13920) or 75 mm (ACI 318), whichever is larger. Many drawings call for 10d.
  • Hook location: in the compression zone at the top of a beam. Never inside a beam–column joint where it clashes with column bars.
  • Laps in stirrups: do not lap a stirrup in the zone where it works hardest. Use a closed shape bent from one bar.

Cutting length and weight

The popular shortcut of subtracting the cover from the beam perimeter hides every bend allowance. This method follows the bar: measure the loop out-to-out, add the hook tails, subtract what the bends save.

Beam 300 mm wide × 500 mm deep (outline) 1234 a = 300 − 2×25 = 250 mm b = 450 cover 25 Out-to-out method L = 2(a + b) + hooks − bend deductions Hooks: 2 × 10d (two 135° tails) Bends: 3 corners at 90° → 3 × 2d 2 hook bends at 135° → 2 × 3d L = 2(a + b) + 20d − 6d − 6d L = 2(a + b) + 8d d = 8 mm → 2(700) + 64 = 1,464 mm Corner dots 1–4 mark the bends. Tails (orange) are the hooks.
Diagram 5. Beam 300 × 500 mm, cover 25 mm, 8 mm stirrup. The loop is out-to-out, so a = 250 mm and b = 450 mm. Allowances used: 2d for a 90° bend, 3d for a 135° bend, 10d for each hook tail.
Cutting length L = 2(250 + 450) + 8 × 8 = 1,464 mm Unit weight w = d² / 162 = 64 / 162 = 0.395 kg/m Weight per piece = 1.464 × 0.395 ≈ 0.58 kg Number of stirrups, 4.0 m clear span, 100 mm in the 2d zones, 150 mm mid: End zones : 900 / 100 = 9 each, ×2 = 18 Middle : (4000 − 1800) / 150 = 14.7 → 15 = 15 Add one for the closing stirrup = 1 Total ≈ 34 pieces → 34 × 0.58 ≈ 20 kg

Different bar-bending schedules use different bend allowances. Britain follows BS 8666 shape codes (a closed stirrup is typically shape code 51), and US detailers use ACI/CRSI standard hooks. Check which table your schedule uses before comparing lengths. A 10 mm variation per piece over 2,000 stirrups is 20 m of steel.

Stirrups vs ties

StirrupTie / hoop
MemberBeams, girders, slabs ribsColumns, piers, piles
Main jobShear and torsionConfinement and bar restraint
Governing checkShear force diagramBar buckling, ductility
Dense zonesNear supports (2d)Ends of column and the joint
ShapesClosed, U, multi-legClosed, circular, spiral, with cross-ties

Some older sources say stirrups go in “horizontal members like columns”. That is a slip: columns are vertical, and their loops are ties. The shapes are identical, but the design logic is not, and that matters when you read a drawing legend.

Walls and retaining structures rarely use classic stirrups. Stem shear is checked on a unit strip and usually carried by concrete alone, with ties only at counterforts and buttresses. See retaining wall types for where that changes. Steel framed floors skip stirrups too, because shear travels through the web of the section; the mezzanine floor types guide shows that comparison.

Site mistakes that weaken stirrups

MistakeWhat it causesCheck
90° hooks on closed stirrupsLoop opens, cover spallsLook at hooks before tying
Spacing opened up at supportsShear cracks where force is highestMark 100 mm zones on the formwork
First stirrup placed 100–150 mm from the faceGap at the critical sectionFirst stirrup at 50 mm
Stirrups left out through the beam–column jointWeak joint, poor confinementCount ties in the joint on the drawing
Stirrups not tied to main barsCage racks while pouringTie at every corner, alternate ties on others
Wrong cut lengthCover problems, loose fitCut one test piece and fit it in the cage
Cover too thin on the stirrupRust stains, early corrosionSpacers under and beside the cage
Bars substituted: 10 mm cut to 8 mmShear capacity drops 36%Compare diameters against the bar schedule

The last row follows from the area: 8 mm bar has 50.3 mm², 10 mm has 78.5 mm², and the difference is a 36% drop in shear steel.

  • Prefabricated stirrup cages. Factory-bent and welded or tied cages, fitted whole. Fewer site cutting errors, faster fixing.
  • Machine-bent stirrups. Bending to a ±2 mm tolerance cuts waste and improves fit in tight beams.
  • GFRP stirrups. Used in marine, bridge and corrosive settings. Capacity depends on the bent portion, which is weaker than the straight leg, so designers apply a reduction factor.
  • Stainless and coated steel. For sea-spray zones and parking decks.
  • Recycled materials. Infrastructure is shifting toward waste-derived inputs, the same direction as plastic roads, though stirrup steel itself is already heavily recycled.

Frequently asked questions

What is the purpose of stirrups in a beam?

They resist shear and torsion, hold the main bars at the correct depth, and keep compression bars from buckling. Shear is the main design reason.

What size stirrups are used in beams?

8 mm is the common size for residential and light commercial beams. Large or heavily loaded beams use 10–16 mm. The structural drawing sets the final size.

What is the standard spacing of stirrups?

Typically 100 mm in the first 2d from each support and 150 mm in the middle. The maximum under IS 456 is 0.75d or 300 mm, whichever is smaller.

What is the difference between 2-legged and 4-legged stirrups?

A 2-legged stirrup puts two bar legs across the section. A 4-legged stirrup uses two overlapping loops, so four legs cross every diagonal crack. That doubles the shear steel at the same spacing.

Why are stirrups closer near the supports?

Shear force is highest at the supports and drops toward mid-span. Tight spacing there puts more steel where diagonal cracks form.

How do you calculate the cutting length of a stirrup?

Measure the loop out-to-out, add hook tails, then subtract bend deductions. For a closed stirrup with two 135° hooks, the result is 2(a + b) + 8d.

Why is a 135° hook required on a stirrup?

It stays anchored in the concrete core when the cover spalls, so the loop keeps confining the bars. A 90° hook can open.

Are stirrups needed in every beam?

Almost always. Codes require minimum shear reinforcement in most beams, and even where calculation shows none is needed, stirrups still position the cage during concreting.

What happens if stirrup spacing is too wide?

Diagonal cracks can pass between stirrups without crossing any, so the beam loses shear capacity and may fail suddenly.

What is the difference between stirrups and lateral ties?

Stirrups are in beams and mainly resist shear. Ties are in columns and mainly confine the core and stop bar buckling.

Sources and references

  • IS 456:2000, Plain and Reinforced Concrete, Clauses 26.5.1.5–26.5.1.6 (stirrup spacing, minimum shear steel) and 40.4 (shear design).
  • IS 13920:2016, Ductile Design and Detailing of Reinforced Concrete Structures Subjected to Seismic Forces.
  • ACI 318-19, Building Code Requirements for Structural Concrete, Chapters 9, 18 and 25.
  • EN 1992-1-1 (Eurocode 2), Clauses 9.2.2 and 9.5.3; EN 1998-1 (Eurocode 8), Clause 5.4.3.1.
  • BS 8666, Scheduling, dimensioning, bending and cutting of steel reinforcement for concrete.

This guide is for learning and planning. A licensed structural engineer must design, detail and approve reinforcement for any real project, and the local code governs.

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